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9x^2+74=54x
We move all terms to the left:
9x^2+74-(54x)=0
a = 9; b = -54; c = +74;
Δ = b2-4ac
Δ = -542-4·9·74
Δ = 252
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{252}=\sqrt{36*7}=\sqrt{36}*\sqrt{7}=6\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-6\sqrt{7}}{2*9}=\frac{54-6\sqrt{7}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+6\sqrt{7}}{2*9}=\frac{54+6\sqrt{7}}{18} $
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